wg.=p0i/ll43'9+1=99pi0o8u%

Audial12 years ago

e^(ix)=cos(x)+isin(x). Let x=pi, therefor e^(i*pi)=cos(pi)+isin(pi) and as cos(pi)=-1 and sin(pi)=0, cos(pi)+isin(pi)=-1, so e^(i*pi)=-1. Maths!